[Baekjoon] 단계별로 풀어보기 2. 조건문 with Python

1330

a, b = map(int, input().split())
if a > b:
    print('>')
elif a < b:
    print('<')
else:
    print('==')

9498

def judge_score(score):
    if score >= 90:
        return 'A'
    elif score >= 80:
        return 'B'
    elif score >= 70:
        return 'C'
    elif score >= 60:
        return 'D'
    else:
        return 'F'

score = int(input())
print(judge_score(score))

2753

def leap_year(year):
    if (year % 4 == 0 and year % 100 != 0) or year % 400 == 0:
        return 1
    else:
        return 0

year = int(input())
print(leap_year(year))

14681

def quadrant(x, y):
    if x > 0 and y > 0:
        return 1
    elif x < 0 and y > 0:
        return 2
    elif x < 0 and y < 0:
        return 3
    else:
        return 4

x = int(input())
y = int(input())
print(quadrant(x, y))

2884

H, M = map(int, input().split())

if H <= 0:
    if M >= 45:
        M -= 45
    elif M < 45:
        H = 23
        M += 15
else:
    if M >= 45:
        M -= 45
    elif M < 45:
        H -= 1
        M += 15

print(H, M)

2525 (시간 분이 60넘어갈 때와, 시가 24 넘어갈 때 생각)

H, M = map(int, input().split())
needs_time = int(input())

H += needs_time // 60
M += needs_time % 60

if M >= 60:
    M -= 60
    H += 1

if H >= 24:
    H -= 24

print(H, M)

2480

def dice(a, b, c):
    if a == b and b == c:
        return 10000 + a*1000
    elif (a == b and b != c) or (a == c and a != b):
        return 1000 + a*100
    elif b == c and a != c:
        return 1000 + b*100
    else:
        return max(a, b, c) * 100

a, b, c = map(int, input().split())
print(dice(a, b, c))